![prepare the truth table of the following statement patterns. (i) [(p → q) ∧ q] → p (ii) (p ∧ q) →∼ p (iii)(p → q) (∼ p ∨ q) (iv) (p r) ∧ (q p) (v) (p ∨∼ q) → (r ∧ p)](https://haygot.s3.amazonaws.com/questions/1188490_1175746_ans_22854732517348a185a6bbd4abb86d72.jpg "prepare the truth table of the following statement patterns. (i) [(p → q) ∧ q] → p (ii) (p ∧ q) →∼ p (iii)(p → q) (∼ p ∨ q) (iv) (p r) ∧ (q p) (v) (p ∨∼ q) → (r ∧ p)")
prepare the truth table of the following statement patterns. (i) [(p → q) ∧ q] → p (ii) (p ∧ q) →∼ p (iii)(p → q) (∼ p ∨ q) (iv) (p r) ∧ (q p) (v) (p ∨∼ q) → (r ∧ p)
SOLVED: Construct a truth table to verify each implication. pAq->-pvq First; complete the truth table below: 7q pAq Zpvq T T F F T F F T F T T F F F T T Therefore, does pAq->-pvq? No 0 Yes
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