Trigonometry
ABC is an isosceles triangle in which AC = BC AD and BE are respectively two altitudes of side BC and AC . Prove that AE = BD .
ABC is an isosceles triangle with AC = BC. If AB^2 = 2AC^2, prove that ABC is a right triangle
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In the given figure, if AOB is a diameter of the circle and AC = BC, then ∠ CAB is equal to
SOLVED: Write an expression describing the shaded portion(s) of the Venn dlagram: AC n BC (A n B)C (A n BF) U (AC n B) (An 89) 0 (AC n B) (A U
Solved Use a truth table to prove that (A B)(AC)-A+ BC 1. | Chegg.com
Solved 3. Show that ( )-1-P(A n B) (b) P(Ac n Bc) = 1-P(A U | Chegg.com
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a^2 ab ac | ba - b^2 bc | ca cb - c^2 = 2a^2b^2c^2
Trigonometry
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ABC is an isosceles triangle in which AC = BC. AD and BE are respectively two altitudes
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Example 17 - Calculate AC, BC, (A + B)C. Also, verify - Examples
Question 5 - ABC is an isosceles triangle with AC = BC. If AB^2 = 2AC^
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![Prove that |[a^2+1,ab,ac],[ab,b^2+1,bc],[ac,bc,c^2+1]|=1+a^2+b^2+c^2](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/642552287_web.png "Prove that |[a^2+1,ab,ac],[ab,b^2+1,bc],[ac,bc,c^2+1]|=1+a^2+b^2+c^2")
Prove that |[a^2+1,ab,ac],[ab,b^2+1,bc],[ac,bc,c^2+1]|=1+a^2+b^2+c^2
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